गणित Class 7 Solutions Chapter 1 Ex 1.4 Ganit पूर्णांक की समझ

Solutions For All Chapters Ganit Class 7

Ex 1.4 – पूर्णांक की समझ

प्रश्न 1. सरल कीजिए

प्रश्न 2. कोष्ठकों का प्रयोग कर निम्नलिखित प्रश्नों को गणितीय रूप दीजिए

(i) (5 + 15) ÷ 8
(ii) 69 ÷ (4 × 6 – 1)
(iii) (24 – 4) ÷ 5 = 4
(iv) 124 ÷ {(25 + 5) + 1}
(v) [{(2 × 4) – 2} × 9] ÷ 6

प्रश्न 3. सरल कीजिए-

(i) 50 + {15 – 5 + (8 – 2)}

उत्तर:

50 + {15 – 5 + (8 – 2)}
= 50 + {15 – 5 + 6}
= 50 + {15 + 1}
= 50 + 16
= 66

(ii) 8 [6 + 2 {5 – 4(5 – 8}]

उत्तर:

8 [6 + 2 {5 – 4(5 – 8)}]
= 8[6 + 2{5 – 4(-3)}]
= 8[6 + 2{5 + 12}]
= 8[6 + 2{17}]
= 8{6 + 34}
= 8 × 40
= 320

(iii) 12 ÷ 6̅ -̅ 2̅ + 10

उत्तर:

12 ÷ 6̅ -̅ 2̅  + 10
= 12 ÷ 4 + 10
= 3 + 10
= 13

(iv) 15 + [2 – 3 – {2 (5 – 4 + 1)}]

उत्तर:

15 + [2 – 3 – {2 (5 – 4 + 1)}]
= 15 + [2 – 3 – {2 (6 – 4)}]
= 15 + [2 – 3 – {2 (2)}]
= 15 + {2 – 3 – 4]
= 15 + [2 – 7]
= 15 + [-5]
= 15 – 5
= 10

(v) 103 – [144 ÷ (12 × 12) + 5 + 12 ÷ 6̅ -̅ 2̅  + 10]

उत्तर:

103 – [144 ÷ (12 × 12) + 5 + 12 ÷ 6̅ -̅ 2̅ + 10]
= 103 – [144 ÷ (12 × 12) + 5 + 12 ÷ 4 + 10]
= 103 – [144 ÷ (144) + 5 + 12 ÷ 4 + 10]
= 103 – [144 ÷ 144 + 5 + 3 + 10]
= 103 – [1 + 18]
= 103 – 19
= 84

(vi) 5 [5 – {5 – (5 – 5 – 5)}]

उत्तर:

5 [5 – {5 – (5 – 5 – 5)}]
= 5 [5 – {5 – (5 – 10)}]
= 5 [5 – {5 – (-5)}]
= 5 [5 – {5 + 5}]
= 5 [5 – {10}]
= 5[5 – 10]
= 5 × -5
= -25

(vii) 15 – (-3) (4 – 4) ÷ {5 + (6) × (-3)}

उत्तर:

15 – (-3)(4 – 4) ÷ {5 + (6) × (-3)}
= 15 – (-3) (4 – 4) ÷ {5 – 18}
= 15 – (-3) (0) ÷ (-13)
= 15 – 0 ÷ (-13)
= 15 – 0
= 15

(viii) (-6) + (-6) ÷ 2 – [(-5) × (-1) – 2 (4 – 2)]

उत्तर:

(-6) + (-6) ÷ 2 – [(-5) × (-1) – 2(4 – 2)]
= -6 – 6 ÷ 2 – [5 – {2(2)}]
= -12 ÷ 2 – [5 – 4]
= -12 ÷ 2 – [1]
= -12 ÷ 2 – 1
= -12 ÷ 1
= -12